Question 239518
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If person 3 had 8 apples left after eating one-third of what remained, then 8 must be two-thirds of what remained.  Let *[tex \Large x] be the number of apples in the bag before ThirdPerson started to eat.  Then:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{2x}{3}\ =\ 8]


Once you solve for *[tex \Large x], you can apply the same logic to figure out what was in the bag before SecondPerson started eating, and then repeat the process one more time to figure out what was in the bag before FirstPerson started to eat, which is the original number of apples in the bag.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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