Question 239047
The base of an isosceles triangle is 12 cm longer than each of its equal legs.
 a second isosceles triangle whose perimeter is 85 cm has a base that is 15 cm shorter than the base of the first triangle. 
each of the equal legs of the second triangle is 8 cm longer than each leg of the first. 
how long are the three sides of each triangle? 
:
label the 1st triangle equal sides as x, then the base = (x+12)
label the 2nd triangle equal sides as (x+8), then the base (x+12)-15 = (x-3)
:
The perimeter equation of the 2nd triangle:
2(x+8) + (x-3) = 85
2x + 16 + x - 3 = 85
3x + 13 = 85
3x = 85 - 13
3x = 72
x = {{{72/3}}}
x = 24
:
Now you should be able to find the length of the other sides of both triangles