Question 238964
If the average (arithmetic mean) of five consecutive integers is m, what is the product of the greatest and least of these five integers?
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Let the consecutive integers be:
m-2
m-1
m
m+1
m+2
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The sum is 5m
The average is m
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Equation:
Product of greatest and least is (m-2)(m+2) = m^2-4
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Cheers,
Stan H. 
a) 4 b) (m+2)^2 c) 2m d) 4m^2 e) m^2 -4
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