Question 238739
Using log rules:

1. logb (ABC) = logb A + logb B + logb C 
2. logb (A/B) = logb A - logb B 
3. logb (A^n) = nlogb A 
4. logb b = 1 
5. logb = logb A1/n = (1/n)logb A n A 
6. logb 1 = 0 
7. logb (1/A) = logb 1 - logb A = -logb A

5*logbx+9*logby-3*logbz 

Use rule 3 first

logb(x^5)+logb(y^9)-logb(z^3)

Use rule 1

logb((x^5 * y^9)/z^3))

log2x+log2(x-6)=4   (assuming base = 2)

log2(x^2-6x) = 4

x^2-6x = 2^4

(x-3)^2-9 = 16

x = 25^1/2 + 3

x = 8 

logbx-(logby+logbz)

logbx-(logb y*z)

logb x/(y*z)