Question 238704
The equation for a Point-Slope Form of a line is:
{{{y-y1=m(x-x1)}}}
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The equation for Slope-Intercept Form of the Line is:
{{{y=mx+b}}}
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Now, all we need to do is substitute the x and y values to answer the question.
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Problem: x-intercept is -6 ; y-intercept is 2
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In the Point-Slope eqn, you substitute the x1 and y1 variables. So:
{{{(y-2)=mx-(-6)}}}
{{{(y-2)=mx+6}}}
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Slope-intercept form:
{{{2=m(-6)+b}}}