Question 238729
The way I would attack this problem is to actually draw the cube which comprises of 3 layers of 9 small cubes all together.

Then looking at the cube you can count the small cubes that have a one face painted and those that have three.

Looking at the larger cube you can see that the the middle smaller cube of each face of the larger cube has one face coloured. So that is 6 small cubes with 1 face.

The small cubes with three faces coloured are the corner ones of the larger face. So that is 8 cubes.

So the answer is 6*8 = 48.

There may be a more mathematical way of doing this that other tutors can elabourate on...

Does this help?