Question 238526
To solve by substitution:
1. Leave first equation alone for now.
2. Solve for y on the second equation.
3. Plug in this value into the first eqn to find x
4. Once you know the x value, plug it again in the forst equation to find y.
.
Problem:
{{{6x+2y-4=0}}}
{{{10x+7y=-8}}}
.
{{{10x+7y=-8}}}
{{{7y=-8-10x}}}
{{{y=(-8-10x)/7}}}
.
{{{6x+2((-8-10x)/7)-4=0}}}
{{{6x+((-16-20x)/7)-4=0}}} ... now multiply by 7 to get rid of fraction
{{{7*6x+7*((-16-20x)/7)-4*7=0}}}
{{{42x-16-20x-28=0}}} ... now combine like terms
{{{22x=16+28}}}
{{{x=44/22}}}
{{{x=2}}}
.
{{{6x+2y-4=0}}}
{{{6(2)+2y-4=0}}}
{{{12+2y-4=0}}}
{{{2y=-8}}}
{{{y=-(8/2)}}}
{{{y=-4}}}
.
Here are your answers: {{{x=2}}} and {{{y=-4}}}