Question 238383
The area of a square of side s is 
{{{A=s^2}}}
The diagonal of the square is 
{{{D=sqrt(2)*s}}}
So area as a function of diagonal is 
{{{A=D^2/2}}}
{{{2A=D^2}}}
The area is proportional to the square of the diagonals.
{{{A1/A2=D1^2/D2^2}}}
{{{3/4=D1^2/D2^2}}}
{{{D1/D2=sqrt(3)/2}}}