Question 238512
find the VA, HA, and OA if they exist
f(x)=3x2-6x-24
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5x2-26x+5 
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HA:y = 3x^2/5x^2 = 3/5
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Factor original to look for VA's:
f(x) = [3(x^2-2x-8)]/[5x^2-25x-x+5]
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f(x) = [3(x-4)(x+2)]/[(x-5)(5x-1)]
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VA: at x = 5 and at x = 1/5
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OA: No OA because the degree of the denominator is
not less than the degree of the numerator.
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Cheers,
Stan H.