Question 238417
sol:
let the angle be x
its complement angle=90-x
according to the problem
x=25+(90-x)
90-x transpose to L.H.S side
x-(90-x)=25
x-90+x=25
2x-90=25
adding 90 on both sides
2x-90+90=25+90
2x=115
dividing by 2 on both sides
2x/2=115/2
x=57.5

sol:
let the angle be x
supplement of angle=180-x
four times  the measure of the angle=4x
according to the problem
supplement of angle=four times measure of angle-45
180-x=4x-45
transpose 45 on L.H.S side and x on R.H.S side
180+45=4x+x
225=5x
dividing both sides by 5
225/5=5x/5
45=x
supplement of angle=180-45=135