Question 238420
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Yes, Pythagoras is the one to use.  But remember, when you construct the altitude of the isosceles triangle, it bisects the base.  So the right triangle you want to calculate has legs that are the slant height of the pyramid which is the height of the isosceles triangle face, and one-half of the base measurement.  Then the hypotenuse is one of the equal legs of the isosceles triangle.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ c\ =\ \sqrt{55.5^2\ +\ 17.2^2}]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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