Question 238342
If a line has slope = {{{m}}}, then
any line perpendicular to it will have
slope = {{{-1/m}}}
{{{y = -3x - 4}}}
{{{m = -3}}}
Perpendicular line J, {{{m[J] = -(1/(-3))}}}
{{{m[J] = 1/3}}}
So far I know line J has the form
{{{y = (1/3)x + b}}}. I know it goes through (1,1),
so I can just plug these values for {{{x}}} and {{{y}}}
back into the equation for J
{{{1 = (1/3)*1 + b}}}
{{{b = 1 - 1/3}}}
{{{b = 2/3}}}
The equation for J is {{{y = (1/3)x + 2/3}}}
I'll plot the 2 lines to check my work
{{{ graph( 400, 500, -5, 5, -5, 5, -3x - 4, (1/3)x + 2/3) }}}