Question 238270
Solve each system by elimination. Check your answers. The first problem is 
x-y+z=-1 
x+y+3z=-3 
2x-y+2z=0
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Subtract 1st from the 2nd;
Subtract 2 times the 1st from the 3rd.
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x-y+z=-1
0x+2y+2z=-2 
0x+y+0z=2
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Solve the 3rd Eq. for y: y = 2
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Substitute y=2 into the 2nd equation and solve for "z":
2*2 + 2z = -2
2Z = -6
z = -3
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Substitute into x-y+z=-1 and solve for "x"
x - 2 - 3 = -1
x = 4
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Solution:
x = 4
y = 2
z = -3
00000000000000000000000000000000000
Cheers,
Stan H.