Question 238264
a triangle has a perimeter of 54 inches. find the length of the three sides if one side is 10 inches longer than the smallest and the third side is twice the smallest.
----------------------
Let the smallest be "x".
The 2nd side is "x+10"
The 3rd side is "2x"
----------------------------
Equation:
x + x+10 + 2x = 54
4x + 10 = 54
4x = 44
x = 11
---------------
smallest = 11 inches
2nd = 11+10 = 21 inches
3rd = 2x = 22 inches
===================================
Cheers,
Stan H.