Question 238194
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The process needed is to complete the prime factorization of the radicand.


360, even so divisible by 2
180, even so divisible by 2
90, even so divisible by 2
45, not even, but digits sum to 9 which is divisible by 3, so is divisible by 3
15, digits sum to 6, so divisible by 3
5, prime.

Prime factors are 2, 2, 2, 3, 3, 5.  Take out one pair of 2s and one pair of 3s leaving a 2 and a 5.  2 times 3 is 6 and 2 times 5 is 10 so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sqrt{360}\ =\ \sqrt{36\,\cdot\,10}\ =\ \sqrt{36}\,\cdot\,\sqrt{10}\ =\ 6\sqrt{10}]




John
*[tex \LARGE e^{i\pi} + 1 = 0]
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