Question 237984
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The only thing you can say is that it is equal to its factors.


Take out a 6


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 6(y^2\ -\ 9)]


Factor the difference of two squares


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 6(y\ +\ 3)(y\ -\ 3)]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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