Question 237841
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Let *[tex \Large x] represent the amount invested at 8.5%.  Then the amount invested at 6% would be *[tex \Large 70000\ -\ x].


The amount of interest earned on the 8.5% money is then *[tex \Large .085x] and the amount of interest earned on the 6% money is *[tex \Large .06(70000\ -\ x)] and these two amounts must add up to $5000.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ .085x\ +\ .06(70000\ -\ x)\ =\ 5000]


Solve for *[tex \Large x] to get the 8.5% amount.  Subtract that from 70000 to get the 6% amount.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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