Question 237709
Supplementary angles add up to 180 degrees.
So, one angle is x; 
the other is 12 more than twice x.
Therefore, here is the eqn:
{{{x+(2x+12)=180}}}
Now solve for x to find the value of one of the angles.
{{{3x=180-12}}}
(((3x=168}}}
{{{x=168/3}}}
{{{x=56}}} ... this is one of the angles.
The other angle is 2x+12, right?  So...
{{{2(56)+12}}}
{{{112+12}}}
{{{124}}}
One angle is 56 degrees, the other is 124 degrees.
Check:
56+124=180