Question 30752
{ { { 5/p^2 - 5/q^2 / 1/p + 1/q } } }

there is no need for the brackets ,,so remove them and we get ...

= 5/p^2 - 5/q^2 / 1/p + 1/q 

thaking LCM a from frist two i.e. 5/p^2 - 5/q^2 and last two i.e. 1/p + 1/q 
 variables we get ...

=(5q^2 - 5p^2)/p^2q^2 / (q+p)/pq

 on solving the equation we get..
=(5q^2 - 5p^2)/[pq *(q+p)]

taking commom from the numerator we get ...

= 5( q^2 - p^2)/ [pq * (q+p)]

now on applying formula a^2 - b^2 = (a+b)(a-b) we get... 

= 5(q+p)(q-p)/ [pq * (q+p)]

[ (q+p) is common in both denominator and numerator  so it will de eliminated ]and we get...

= 5(q-p) / pq

= (5q - 5p )/ pq

hope this will help you...

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