Question 237533
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ y\ =\ 12]


Add *[tex \Large -x] to both sides


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ -\ x\ +\ y\ =\ 12\ -\ x]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ 12\ -\ x]


NOW make the substitution:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x\ -\ 3(12\ -\ x)\ =\ 6]


You should be able to take it from there.  Write back if you need more help.  Hint:  The values of x and y are both fairly ugly fractions.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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