Question 237521
{{{x^2+(3-2)=0}}}
{{{x^2+1=0}}}
If you move the 1 over to the right, you'd get:
{{{x^2=-1}}} ...which is not possible.
No number raised to the second power equals a negative number.
The only exception is if you're working with imaginary numbers.
In which case the answer would be...
x = sqrt -1 ...same as... x = sqrt of i