Question 237524
You can write this problem algebraically this way:
{{{(x+10)+x=16}}}
Then solve for x.
{{{2x=16-10}}}
{{{2x=6}}}
{{{x=6/2}}}
{{{x=3}}}
You can check your result by substituting this value in the original equation to ensure it matches.
So, one number is x+10=13
the other is x=3
When you add them both, your result is 16.