Question 237518
I am trying to find the derivative of (1/x)
I need to see how to get passed the step of putting (x+h) in and dividing everything by h. 
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f(x+h) = 1/(x+h)
f(x) = 1/x
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f(x+h)-f(x)=[1/(x+h) - 1/x] = [x-(x+h)]/[x(x+h)]
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= [-h]/[x^2+hx]
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Now divide by "h" to get:

= [-1]/[x^2+hx]

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Cheers,
Stan H.