Question 237395
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Solve the given equation for *[tex \Large y] to put it into slope-intercept form.  Then determine the slope of the given line by inspection of the coefficient on *[tex \Large x]


Now use the fact that the slopes of perpendicular lines are negative reciprocals, that is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  L_1 \perp L_2 \ \ \Leftrightarrow\ \ m_1 = -\frac{1}{m_2} \text{ and } m_1, m_2 \neq 0]


To calculate the slope of the desired line.


Finally, use the point-slope form of the equation of a line to derive the required equation:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y - y_1 = m(x - x_1) ]


Where *[tex \Large \left(x_1,y_1\right)] are the coordinates of the given point and *[tex \Large m] is the calculated slope.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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