Question 236838
f(x)=(2x+1)/(x-1)
y=( 2x+1)/(x-1)
y(x-1)=2x+1 Now we solve for x.
xy-y=2x+1
xy-2x=y+1 Get the x's on one side.
x(y-2)=y+1
x=(y+1)/(y-2)
y=(x+1)/(x-2) Switch x and y
{{{f^(-1)(x)=(x+1)/(x-2)}}} the inverse.
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Ed