Question 236726
You have the right ideas. There's just a slight flaw in your factoring:
{{{((6x^2-18x)/(3x^2-2x))*((15x-10)/(x^2-9))}}}
which factors into
{{{((6x(x-3))/(x(3x-2)))*((5(3x-2))/((x+3)(x-3)))}}}
Canceling common factors:
{{{((6*cross(x)*cross((x-3)))/(cross(x)*cross(3x-2)))*((5*cross((3x-2)))/((x+3)*cross((x-3))))}})
leaving:
{{{(6/1)(5/(x+3))}}}
which simplifies to:
{{{30/(x+3)}}}