Question 236777

What is "log base 5 times the quantity (x-1) minus log base 5 times quantity (x-2) equals 2" ? 
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{{{log(5,(x-1)) - log(5,(x-2)) = 2)}}}
Applying "log rules"...
{{{log(5,(x-1)/(x-2)) = 2)}}}
{{{(x-1)/(x-2) = 5^2)}}}
{{{(x-1)/(x-2) = 25)}}}
{{{(x-1) = 25(x-2))}}}
{{{x-1 = 25x-50)}}}
{{{-1 = 24x-50)}}}
{{{49 = 24x)}}}
{{{49/24 = x)}}}