Question 236615
{{{2 log ( x ) + 3 log ( y ) - log ( 7 )}}}
You got as far as:
{{{log((x^2*y^3)) - log((7))}}}
which is correct. Now we just use the "other" property of logarithms:
{{{log(a, (p)) - log(a, (q)) = log(a, (p/q))}}}
to combine the remaining two logarithms giving:
{{{log((x^2*y^3/7))}}}<br>
The original expression required that both x and y be positive numbers. This is still true for the combined, single logarithm (even though it may appear that x could be a negative because it is squared).