Question 236580


{{{(2h^3-2h^2-12h)/(h^2-5h+6)}}} Start with the given expression.



{{{(2h(h+2)(h-3))/(h^2-5h+6)}}} Factor {{{2h^3-2h^2-12h}}} to get {{{2h(h+2)(h-3)}}}.



{{{(2h(h+2)(h-3))/((h-2)(h-3))}}} Factor {{{h^2-5h+6}}} to get {{{(h-2)*(h-3)}}}.



{{{(2h(h+2)highlight((h-3)))/((h-2)highlight((h-3)))}}} Highlight the common terms. 



{{{(2h(h+2)cross((h-3)))/((h-2)cross((h-3)))}}} Cancel out the common terms. 



{{{(2h(h+2))/(h-2)}}} Simplify. 



{{{(2h^2+4h)/(h-2)}}} Distribute. 



So {{{(2h^3-2h^2-12h)/(h^2-5h+6)}}} simplifies to {{{(2h^2+4h)/(h-2)}}}.



In other words, {{{(2h^3-2h^2-12h)/(h^2-5h+6)=(2h^2+4h)/(h-2)}}}