Question 236455
{{{(8-y)/(2-y)}}} Start with the given expression.



{{{(-(-8+y))/(2-y)}}} Factor a -1 from the numerator.



{{{(-(-8+y))/(-(-2+y))}}} Factor a -1 from the denominator.



{{{(-(y-8))/(-(y-2))}}} Rearrange the terms.



{{{(y-8)/(y-2)}}} Reduce. In other words, simplify {{{-1/-1}}} to get 1 (which is then absorbed into the expression).



So {{{(8-y)/(2-y)=(y-8)/(y-2)}}} where {{{y<>2}}}