Question 236035
4x^3+4x^2y-24xy^2


factor out 4x to get:


4x * (x^2 + xy - 6y^2)


if you didn't have the y there, your equation within the parentheses would have been:


x^2 + x - 6 which factors as (x+3) * x-2)


if you add a y into the right side of each of the factors, you get:


x^2 + xy - 6y^2 = (x+3y) * (x-2y)


this looks like it will actually work.


your factors should be:


4x * (x+3y) * (x-2y)


to confirm they are good, work back to see if you can get the original equation again.


(x + 3y) * (x-2y) becomes:


x^2 - 2xy + 3xy - 6y^2 which becomes


x^2 + xy - 6y^2


multiply that by 4x to get:


4x * (x^2 + xy - 6y^2) becomes:


4x^3 + 4x^2y - 24xy^2


your original equation is:


4x^3 + 4x^2y - 24xy^2


since they're the same, your answer is confirmed.


your answer is:


4x * (x+3y) * (x-2y)