Question 236058
If the roots are x = -4 and x = 3, then the equation would be:


(x+4) * (x-3) = 0


Multiply these factors together to get:


x^2 + x - 12 = 0


Since your c factor has to be 4, then you need to divide both sides of this equation by -3 to get:


-x^2/3 - x/3 + 4 = 0


This would be the same as:


-(1/3)*x^2 - (1/3)*x + 4 = 0


a would be equal to -(1/3)
b would be equal to -(1/3)
c would be equal to 4


If you were given this equation in this form to start with and asked to solve for the roots, you would have done the following:


Multiply both sides of the equation by (-3) to get:


x^2 + x - 12 = 0


Factor this equation to get:


(x-3) * (x+4) = 0


Solve for x to get:


x = 3
or:
x = -4


which is where you started from.