Question 236145
your equation is f(x) = (3x-1)


They want you to evaluate {{{(f(x)-f(1))/(x-1)}}}


If so, this is how you do it.


Let g(x) = {{{(f(x)-f(1))/(x-1)}}}


You replace f(x) with (3x-1) because that's what f(x) is equal to.


You replace x with 1 in f(x) = 3x-1 to get f(1) = 3*1-1 = 2


You are left with:


g(x) = {{{(f(x)-f(1))/(x-1)}}} = {{{((3x-1) - 2)/(x-1)}}}


This becomes:


g(x) = {{{(3x-3)/(x-1)}}}


You can factor the numerator to get


g(x) = {{{(3x-3)/(x-1)}}} = {{{(3*(x-1))/(x-1)}}}


This becomes:


g(x) = 3