Question 236048
 how many kilograms of water must be added to 10 kg of a 75% antifreeze solution in order to produce a 50% solution?
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Let "x" be the amount of water added.
Equation:
alcohol + alcohol = alcohol
0.75(10) + 0(x) = 0.50(10+x)
Multiply thru by 100 to get:
75*10 = 50*10 + 50x
50x = 25*10
x = 5 kg (amount of water needed in the mixture)
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Cheers,
Stan H.