Question 236031
Table I 
  	        White  Black  Hispanic  Asian  Foreign 	   Total 
Dept. 1.          4	 0	 1	  1	  2	     8
Dept. 2.          2	 4	 1	  1	  0	     8
Dept. 3.          1	 2	 3	  1	  1	     8
Dept. 4.          4	 0	 1	  1	  2	     8
Dept. 5.          3	 2	 1	  0	  2	     8  
Total. 	         14	 8	 7	  4	  7	     40

    Table II 
  	 Female  Male 	Total 
Black 	   6	  2	  8
White 	   6	  8	  14
Hispanic   3	  4	  7
Asian 	   2	  2	  4
Foreign    5	  2	  7
Total 	   22	  18	  40
From Table 1: What is the probabilty of choosing a White employee from Dept. 2 and then a Hispanic employee from Dept. 3?
(2/40) * (3/38) = (1/20)*(3/38) = 3/760
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What is the probability of choosing a Foreigner or an Hispanic both from Department 5?
(1+2)/40 = 3/40
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From Table 2: What is the probability of choosing a Black male or a Foreign male?
(2+2)/40 = 1/10
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Cheers,
Stan H.