Question 235981
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The perimeter of a rectangle is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P\ =\ 2l\ +\ 2w]


but we want to fix the width at 10 and hold the perimeter greater than 82, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2l\ +\ 2(10)\ >\ 82]


Solve for *[tex \Large l]:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2l\ >\ 62]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ l\ >\ 31]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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