Question 235835
I'll do the first three to get you started. The rest will be similar to these problems.



1) {{{6^(1/2)^""=sqrt(6^1)=sqrt(6)}}}



2) {{{4^(2/3)^""=root(3,4^2)=root(3,16)}}}



3) {{{(5x)^(2/5)^""=root(5,(5x)^2)=root(5,25x^2)}}}



Note: I'm using the identity {{{(x)^(m/n)^""=root(n,x^m)}}} where {{{x>=0}}}