Question 235440
Assume the problem is:
{{{((2x-4))/(xy^2)}}}
------------
{{{((3x-6y))/(x^3y)}}}
:
Invert the dividing fraction and multiply
{{{((2x-4))/(xy^2)}}} * {{{(x^3y)/((3x-6y))}}}
;
Factor and cancel the xy's
{{{(2(x-2))/(y)}}} * {{{(x^2)/(3(x-2y))}}} = {{{(2x^2(x-2))/(3y(x-2y))}}}
;