Question 234789
a^-2b^2
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ac
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ab
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b^-2c^3
Invert the lower fraction and mutiply
= {{{(a^(-2)b^2)*(b^-2c^3)/(ac*bc)}}}
= {{{a^(-2)c^3/abc^2}}}
= {{{a^(-2)c/ab}}}
= {{{c/a^3b}}}