Question 235686
Please find the vertex, y intercept and x intercept and graph the following equation: x^2 + 8x + 7 = y
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Vertex occurs where x = -b/2a = -8/2 = -4
f(-4) = (-4)^2+8(-4)+7 = 16-32+7 = -9
So vertex is (-4,-9)
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y-intercept at f(0) = 7
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x-intercepts when y = 0:
x^2+8x+7 = 0
(x+7)(x+1) = 0
x = -7 or x = -1
Those are the x-intercepts.
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{{{graph(400,300,-10,10,-10,10,x^2+8x+7)}}}
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Cheers,
Stan H.