Question 235627
3log2x-log2x=8
{{{log(2,x^3)-log(2,x)=8}}}
{{{log(2,(x^3/x))=8}}}
{{{2^8=x^3/x}}}
{{{256=x^3/x}}}
and thats as far as i got
{{{256 = x^2}}}
x = ±16
Since it's inside the log function, the -16 is rejected.
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You were almost there.
I don't see how it can be 8, unless there's a typo.