Question 235363
Assuming the problem is:
{{{((y+1))/((y+10))}}} = {{{((y-2))/((y+4))}}}
Cross multiply
:
(y+1)(y+4) = (y+10)(y-2)
FOIL
y^2 + 5y + 4 = y^2 + 8y - 20
:
Arrange the y's on the left
y^2 - y^2 + 5y - 8y = -20 - 4
:
-3y = -24
Which is
3y = 24
y = {{{24/3}}}
y = 8
;
:
Check solution in original equation
{{{((8+1))/((8+10))}}} = {{{((8-2))/((8+4))}}}
{{{((9))/((18))}}} = {{{((6))/((12))}}}