Question 235501
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \tan\Theta\ =\ \frac{\sin\Theta}{\cos\Theta}]


Therefore:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \cos\Theta\ =\ \frac{\sin\Theta}{\tan\Theta}]


so, just divide *[tex \Large \frac{4}{5}] by *[tex \Large \frac{4}{3}], which is to say multiply *[tex \Large \frac{4}{5}] by *[tex \Large \frac{3}{4}]


And by the way, *[tex \Large \Theta] is the larger acute angle in a 3-4-5 right triangle.


Stanbon's analysis below is flawed in that he should have said *[tex \Large x\ =\ \sqrt{5^2-4^2}\ =\ \sqrt{9}\ =\ 3]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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