Question 235352
Since one given solution is x=4, this means that x=4 satisfies the equation {{{kx^2-7x+k=0}}}. So just plug that value into the equation and solve for k:



{{{k(4)^2-7(4)+k=0}}} ---> {{{16k+k-28=0}}} ---> {{{17k=28}}} ---> {{{k=28/17}}}



This means that the equation then becomes {{{(28/17)x^2-7x+28/17=0}}}. From here, just use the quadratic formula to find the other solution.