Question 235035
What is the probability that a 89% foul shooter will make at least 2 shots in a basketball game? 
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P(2<= x <=89) = 1 - P(0<= x <= 1)
= 1 - [2C0(0.89)^0(0.11)2 + 2C1(0.89)(0.11)]
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= 1 -[0.2079]
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= 0.7921
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Cheers,
Stan H.