Question 235118
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Let *[tex \Large d] represent the number of dimes.  Then the number of quarters must be *[tex \Large 2d\ +\ 1]


Since each dime is worth 10 cents, the value of the dimes, in cents is:  *[tex \Large 10d].  Likewise, the value of the quarters, each worth 25 cents, must be *[tex \Large 25(2d\ + 1)]


The value of the dimes plus the value of the quarters must equal the total value of all the coins, which is given as $5.05, but which can be expressed as 505 cents.  So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 10d\ +\ 25(2d\ +\ 1)\ =\ 505]


Just solve for *[tex \Large d] to get the number of dimes, double that and add one to get the number of quarters.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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