Question 235094
Are you supposed to draw the graph?


The slope is (7/3)


That means that for every change of  3 in x, you get a change of 7 in y.


7 is the y-intercept.


The slope-intercept form of the equation of a straight line is y = mx + b


In your equation, m = (7/3) and b = 7


To graph, just plot some points.


Pick multiples of 3 for x to make the math go easier.


When x = 0, y = 7/3 * 0 + 7 which makes it equal 7.


When x = 3, y = 7/3 * 3 + 7 which makes it equal to 7 + 7 = 14


When x = 6, y = 7/3 * 6 + 7 which makes it equal to 14 + 7 = 21


Plot the points:


(x,y)


(0,7)
(3,14)
(6,21)


and you have your straight line graphed.


The graph would look like:


{{{graph(600,600,-15,15,-35,35,(7/3)*x+7)}}}


A picture of the graph showing the intersection points can be found <a href = "http://theo.x10hosting.com/problems/235094.html" target = "_blank">here !!!!!</a>


The picture shows that when:


x = 0, (7/3)*0 + 7 = 0 + 7 = 7


x = 3, (7/3)*3 + 7 = 7 + 7 = 14


x = 6, (7/3)*6 + 7 = 14 + 7 = 21