Question 235092
3 / (7-sqrt(2))


To remove the square root from the denominator, multiply numerator and denominator by (7+sqrt(2)


you get:


3 * (7+sqrt(2)) / 49 - 2 which equals:


21 + 3*sqrt(2) / 47


If "21 + 3 to the radical of 2 over 47" is the same as "21 + 3*sqrt(2)" then you got it right.


sqrt(2) looks like {{{sqrt(2)}}} after going through the algebra.com formula generator.


It's not 3 to the radical of 2.


It would be 3 times the radical of 2.


I would say it as 3 times the square root of 2.


The answer would look like {{{(21 + 3*sqrt(2))/47}}}