Question 235084
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The area of a triangle is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ \frac{bh}{2}]


where


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ b] is the measure of the base and *[tex \LARGE h]is the measure of the height


So, just replace the variables for base and height with your expressions:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A(x)\ =\ \frac{6x(9x\ -\ 1)}{2}\ =\ \frac{54x^2\ -\ 6x}{2}\ =\ 27x^2\ -\ 3x]


And


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A(50)\ =\ 27(50)^2\ -\ 3(50)]


You can do your own arithmetic.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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