<PRE><B>Question 235050</B>
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You gave *[tex \LARGE f(x)\ =\ 10y^2\ +\ 9y\ -\ 6]


That is a &lt;b&gt;&lt;i&gt;very&lt;/i&gt;&lt;/b&gt; strange way to define a function of the variable &lt;b&gt;&lt;i&gt;x&lt;/i&gt;&lt;/b&gt;.


The answer, as you posed the question, is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(-2)\ =\ 10y^2\ +\ 9y\ -\ 6]


No matter what value you assign to the variable &lt;b&gt;&lt;i&gt;x&lt;/i&gt;&lt;/b&gt;, the answer is still going to be:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(\text{whatever})\ =\ 10y^2\ +\ 9y\ -\ 6]


Now, if what you &lt;b&gt;&lt;i&gt;really&lt;/i&gt;&lt;/b&gt; meant to say was:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(y)\ =\ 10y^2\ +\ 9y\ -\ 6]


Then


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(-2)\ =\ 10(-2)^2\ +\ 9(-2)\ -\ 6]


I&#39;ll let you do your own arithmetic.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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